3=2x^2+5

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Solution for 3=2x^2+5 equation: 



3=2x^2+5

We move all terms to the left:

3-(2x^2+5)=0

We get rid of parentheses

-2x^2-5+3=0

We add all the numbers together, and all the variables

-2x^2-2=0

a = -2; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·(-2)·(-2)
Δ = -16
Delta is less than zero, so there is no solution for the equation

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